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    <p>OK, I've fixed it. Man was that hard! Mainly because you forgot to set the imageCanvas' canvas height. It also didn't help that the image has a white border. I spent a hell of a lot of time trying to figure out where the padding was coming from. </p> <p>So to start, for the case of the <a href="http://jsfiddle.net/254ck/4/">fiddle</a>, in function <code>doBlending()</code>, set <code>imageCanvas.canvas.height = height;</code></p> <p>Then the calculations in <code>crop()</code> need to cover 2 possibilities. Is the image being scaled for height and truncated on the left or scaled for width and truncated on the bottom? I'm not going to write both for you, but here's the one for the case where it is scaled for height:</p> <pre><code>function crop(imageObj, imageCanvas, colorCanvas) { // Assumes bg image is scaled for hight var scale = imageObj.height / window.innerHeight; var targetHeight = imageCanvas.canvas.height; var targetWidth = window.innerWidth; imageCanvas.drawImage(imageObj, 0, 0, targetWidth * scale, targetHeight * scale, 0, 0, targetWidth, targetHeight); } </code></pre> <p>I really have no idea where you came up with the scaling factors in your example. The image is going to be scaled by multiplying both the x and y dimensions by some scale factor. That's how you preserve the aspect ratio. The scale factor will be the larger of the one to make the height of the image match the height of the window and the one to make the width of the image match the width of the window.</p>
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    1. COThe white border was because of fiddle (I think). In the original code, there's no white border. The case here is always to match the width of the background-image and truncate on the bottom to get a height of 192px. I guess I did complicate things a lot.
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    2. COThe white border is part of [the image](http://www.bittbox.com/wp-content/uploads/2007/02/vector_perforated_metal_pattern.png) as stored on bittbox. With the fiddle, matching the width doesn't work if the result area's aspect ratio (width / height) is less than the source image's because of the way `cover` works.
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