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    <p>I need to know a bit more to answer your question properly, but here are some ideas that might help you. I'm making the assumption that <code>photos_list</code>, <code>places_list</code> and <code>events_list</code> are all objects of different classes that are Django models.</p> <p><strong>Option 1: Define a method on each class that determines the type of the object</strong></p> <p>For example, define a <code>content_type</code> method on each model, like this:</p> <pre><code>class Photo(models.Model): def type(self): return 'photo' </code></pre> <p>And then check this in your template:</p> <pre><code>{% for item in result_list %} {% if item.type == "photo" %} ... {% elif item.type == "place" %} ... {% else %} ... {% end %} {% endfor %} </code></pre> <p><strong>Option 2: Define a <code>render</code> method on each class</strong></p> <p>This is probably much uglier, but you could define a <code>render</code> method on each object that returns the complete HTML you want to spit out for that object. Then it's a case of doing this in your template:</p> <pre><code>{% for item in result_list %} {{ item.render }} {% endfor %} </code></pre> <p><strong>Sidenote: Consider inheritance</strong></p> <p>It sounds like photos, places and events are all things that could appear in the same feed, and as such they might share some common fields (like <code>posted_at</code>). There are various things you need to consider with regard to this, so it's probably best to look at the <a href="https://docs.djangoproject.com/en/dev/topics/db/models/#model-inheritance" rel="nofollow">Django documentation on model inheritance</a>.</p>
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    1. COHello , thank you for the replay , sorry forget to mention that " photo , event , place " are different models
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    2. COMy answer assumes that they are different models, so that's fine.
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    3. COWorking , all of them tried them all THANK YOU :D
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