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  1. PO
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    <p>Firstly, am I right in assuming that this is a learning exercise for you in learning "how to create your own string class"? C++ has already got a built-in <em>string</em> type which you should always prefer for the most part.</p> <p>the <code>sizeof</code> operator yields the size (in bytes) of its operand, which in this case is <strong>c</strong> whose type is <code>char*</code> - it looks like what you're actually after is the length of a null-terminated character array (a "C" string") - you're already using <em>strlen</em>, so I'd suggest you simply want to use that again. (taking a null-terminator into account too)</p> <pre><code>name = resize(name, l, strlen(c) + 1); </code></pre> <p>Note, that your code looks as if it suffers from memory leaks. You're assigning a new value to your <em>name</em> variable without clearing up whatever existed there first.</p> <pre><code>if(l &lt; strlen(c)+strlen(name)) { char* my_new_string = resize(name, l, strlen(c)); if( my_new_string != NULL ) { delete [] name; name = my_new_string; } } </code></pre> <p><em>EDIT</em>: As other replies have pointed out, there's still plenty wrong with the code which could be resolved using C++'s <code>string</code> and <code>vector</code>. </p> <p>Here's one possible way you could implement add_chars</p> <pre><code>void MyString::add_chars(char* c) { if( c != NULL &amp;&amp; name != NULL ) { size_t newlength = strlen(c) + strlen(name) + 1; char* newstring = new char[newlength]; if( newstring != NULL ) { size_t namelength = strlen(name); size_t remaining = newlength - namelength; strncpy( newstring, name, newlength ); strncpy( &amp;newstring[namelength] , c, remaining ); delete [] name; name = newstring; } } } </code></pre>
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    1. POAdd characters to a character array c++
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    1. COYou got the half that Tony missed, but missed the parts he has.
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