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POBison - how to print a parse tree
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10247206
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AcceptedAnswerId
10248270
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1
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0
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CreationDate
2012-04-20T13:28:11.063
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2
LastActivityDate
2012-04-20T15:45:02.297
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0
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491753
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0
PostTypeId
1
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2
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5687
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text
Body
Hi I'm working on a small bison to learn how it works. The bison is supposed to parse a sentence. The sentence is made of expressions and expressions are made of words. Following is my code: <pre><code>%{ #include <stdio.h> #include <string.h> void yyerror(const char *str) { fprintf(stderr,"error: %s\n",str); } int yywrap() { return 1; } main() { yyparse(); } %} %token ASSIGN RANGE OR AND WHITESPACE QUOTE LPAREN RPAREN NOT GREATER LESS %union { int number; char *string; } %token <number> VALUE %token <string> WORD %type <string> term %type <string> expression %% query: /* empty */ | query expression { printf("WOrd:%s",$2); } ; expression: term |expression term |expression AND term { printf("AND"); } ; term: WORD { $$=$1; } ; </code></pre> So, when user enters a word, it supposed to print out the word. User should be able to type in: word,word word,word and word I'm not sure how to pass a word using $$ and print it out from the "query expression" rule. How do I do this? this is my flex: <pre><code>%{ #include <stdio.h> #include <string.h> #include "y.tab.h" %} %% [0-9]+ yylval.number=atoi(yytext);return VALUE; [a-zA-Z][a-zA-Z]* yylval.string=strdup(yytext);return WORD; ":" return ASSIGN; "and"|"&"|"&&" return AND; ".." return RANGE; "-" return NOT; "|" return OR; "\"" return QUOTE; ">" return GREATER; "<" return LESS; \n /* ignore end of line */; \t /* ignore end of line */; %% </code></pre> THanks so much in advance. Sarah
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<bison>
Title
Bison - how to print a parse tree
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1. PO
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1. USsap
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1. PO
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1. VO
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 POBison - how to print a parse tree
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