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POPub Sub implementation zero mq 3.xx
 

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    <p>I have been working with qpid and now i am trying to move to broker less messaging system , but I am really confused about network traffic in a Pub Sub pattern. I read the following document : <a href="http://www.250bpm.com/pubsub#toc4" rel="nofollow">http://www.250bpm.com/pubsub#toc4</a> and am really confused how subscription forwarding is actually done ?</p> <p>I thought zero mq has to be agnostic for the underlying network topology but it seems it is not. How does every node knows what to forward and what to not (for e.g. : in eth network , where there can be millions subscriber and publisher , message tree does not sound a feasible to me . What about the hops that do not even know about the existence of zero mq , how would they forward packets to subscribers connected to them , for them it would be just a normal packet , so they would just forward multiple copies of data packets even if its the same packet ? I am not networking expert so may be I am missing something obvious about message tree and how it is even created ? Could you please give certain example cases how this distribution tree is created and exactly which nodes are xpub and xsub sockets created ?</p> <p>Is device (term used in the link) something like a broker , in the whole article it seemed like device is just any general intermediary hop which does not know anything about zero mq sockets (just a random network hop) , if it is indeed a broker kind of thing , does that mean for pub sub , all nodes in messaging tree have to satisfy the definition of being a device and hence it is not a broke less design ?</p> <p>Also in the tree diagram (from the link , which consist P,D,C) , I initially assumed C and C are two subscribers and P the only publisher (D just random hop), but now it seems that we have D as the zero mq . Does C subscribes to D and D subscribes to P ? or both the C just subscribe to P (To be more generic , does each node subscribe to its parent only in the ). Sorry for the novice question but it seems i am missing on something obvious here, it would be nice if some one can give more insights.</p>
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