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POHow to draw a tree representing a graph of connected nodes?
 

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  1. POHow to draw a tree representing a graph of connected nodes?
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    <p>I want to display a tree in a Java GUI, but I dont know how. The tree represents a graph of connected nodes, like this:</p> <p><img src="https://upload.wikimedia.org/wikipedia/commons/thumb/f/f7/Binary_tree.svg/300px-Binary_tree.svg.png" alt="image"></p> <p>I should say that I have my own tree class:</p> <pre><code>public class BinaryTree { private BinaryNode root; public BinaryTree( ) { root = null; } public BinaryTree( Object rootItem ) { root = new BinaryNode( rootItem, null, null ); } public BinaryTree( Object rootItem,BinaryNode a,BinaryNode b ) { root = new BinaryNode( rootItem, a, b ); } public int leavesCount(){ return BinaryNode.leavesCount(root); } public boolean equal(BinaryTree a,BinaryTree b){ return BinaryNode.equal(a.root, b.root); } public void printPreOrder( ) { if( root != null ) root.printPreOrder( ); } public void printInOrder( ) { if( root != null ) root.printInOrder( ); } public void printPostOrder( ) { if( root != null ) root.printPostOrder( ); } public void makeEmpty( ) { root = null; } public boolean isEmpty( ) { return root == null; } public void merge( Object rootItem, BinaryTree t1, BinaryTree t2 ) throws MergeAbrot { if( t1.root == t2.root &amp;&amp; t1.root != null ) { throw new MergeAbrot("MergeAbrot"); } root=new BinaryNode( rootItem, t1.root, t2.root ); if( this != t1 ) t1.root = null; if( this != t2 ) t2.root = null; } public int size( ) { return BinaryNode.size( root ); } public int height( ) { return BinaryNode.height( root ); } } </code></pre> <p>I only want to draw the tree. How should I do?</p>
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