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    <p>David's solution is the best.</p> <p>But probably more for fun than anything, here is a solution that does not import any module:</p> <pre><code>dicto = {} for ele in mylist: try: dicto[ele] += 1 except KeyError: dicto[ele] = 1 top_10 = sorted(dicto.iteritems(), key = lambda k: k[1], reverse = True)[:10] </code></pre> <p>Result:</p> <pre><code>&gt;&gt;&gt; top_10 [('and', 13), ('all', 2), ('as', 2), ('borogoves', 2), ('boy', 1), ('blade', 1), ('bandersnatch', 1), ('beware', 1), ('bite', 1), ('arms', 1)] </code></pre> <p>EDIT:</p> <p>Answering the follow up question:</p> <pre><code>new_dicto = {} for val, key in zip(dicto.itervalues(), dicto.iterkeys()): try: new_dicto[val].append(key) except KeyError: new_dicto[val] = [key] alph_sorted = sorted([(key,sorted(val)) for key,val in zip(new_dicto.iterkeys(), new_dicto.itervalues())], reverse = True) </code></pre> <p>Result:</p> <pre><code>&gt;&gt;&gt; alph_sorted [(13, ['and']), (2, ['all', 'as', 'borogoves']), (1, ['"and', '"beware', '`twas', 'arms', 'awhile', 'back', 'bandersnatch', 'beamish', 'beware', 'bird', 'bite', 'blade', 'boy', 'brillig'])] </code></pre> <p>The words that show up once are sorted alphabetically, if you notice some words have extra quotation marks in them.</p> <p>EDIT:</p> <p>Answering another follow up question:</p> <pre><code>top_10 = [] for tup in alph_sorted: for word in tup[1]: top_10.append(word) if len(top_10) == 10: break </code></pre> <p>Result:</p> <pre><code>&gt;&gt;&gt; top_10 ['and', 'all', 'as', 'borogoves', '"and', '"beware', '`twas', 'arms', 'awhile', 'back'] </code></pre>
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    1. POhow to get the 10 most frequent strings in a list in python
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    1. COhow then would you be able to just get the words and for the words that have the same number, how would you put them in alphabetical order
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      1. USKeely Aranyos
    2. COhow would you get the top 10 of the alph sorted
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    3. CO@KeelyAranyos I edited my post to answer your second question, hopefully it gives you what you are looking for.
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