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    <p>Elaborating on @Vacuum's comment</p> <p>Here's a simple way (untested, but I believe this would work)</p> <p>1) Create a new class ExUsernamePasswordAuthenticationFilter that will extend the default filter and grab the additional parameter and store it in the session. It will look something like this:</p> <pre><code> public class ExUsernamePasswordAuthenticationFilter extends UsernamePasswordAuthenticationFilter { @Override public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException { final String dbValue = request.getParameter("dbParam"); request.getSession().setAttribute("dbValue", dbValue); return super.attemptAuthentication(request, response); } } </code></pre> <p>2) In your UserDetailsService implementation, modify your implementation of:</p> <pre><code>UserDetails loadUserByUsername(String username) throws UsernameNotFoundException, DataAccessException; </code></pre> <p>to grab the session variable that the filter from step 1) makes available. </p> <p>3) in your <code>&lt;http /&gt;</code> security set-up, override the default filter with your custom one</p> <pre><code>&lt;custom-filter ref="beanForYourCustomFilterFromStep1" position="FORM_LOGIN_FILTER"/&gt; </code></pre> <p>Refer to this part of the documentation for more info about custom filters: <a href="http://static.springsource.org/spring-security/site/docs/3.1.x/reference/springsecurity-single.html#ns-custom-filters" rel="noreferrer">http://static.springsource.org/spring-security/site/docs/3.1.x/reference/springsecurity-single.html#ns-custom-filters</a></p>
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    1. POHow to pass an additional parameter with spring security login page
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    1. COThanks a lot for your information. I implemented it, it worked well.
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    2. COThere is less invasive way of doing this and without violating the contract of `UserDetailsService`. I agree with @sourcedelica. Also eee my [answer](http://stackoverflow.com/a/16155696/719633) to similar question for more detailed example.
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