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    <p>It looks to me like you are checking for <code>$_POST["staffid"]</code>, but your select menus have <code>name="attendance_status"</code> set. </p> <p>You should rather set the names of your select menus like this:</p> <pre><code>name="attendance_status[]" </code></pre> <p>Then in your php script you read an array - not a single value - when you do <code>$_POST["attendance_staff"]</code>.</p> <p>EDIT: This will only work if you also have an array available with all the corresponding staffids. You can get this by using a hidden input for every row whose name is <code>staffid[]</code> and whose value is the staffid.</p> <p>However, a more reliable way would probably be to use the staffid inside the name of every saveable form element, as David-SkyMesh pointed out in a comment to your post.</p> <p>EDIT: For example, you could use this code to name your form elements (untested):</p> <pre><code>&lt;select name="$staffID_attendance_status" id="$staffID_attendance_status"&gt; &lt;option value="Present"&gt;Present&lt;/option&gt; &lt;option value="Absent"&gt;Absent&lt;/option&gt; &lt;/select&gt; &lt;textarea cols="21" rows="5" name="$staffID_notes" id="$staffID_notes" placeholder="Enter notes here..."&gt;&lt;/textarea&gt; &lt;input type='hidden' name='staffID[]' value='$staffID'&gt; </code></pre> <p>Note that this will also give all your form elements unique ids which is necessary if you want your HTML to validate.</p> <p>Then in your script you could do this:</p> <pre><code>foreach ($_POST["staffID"] as $staffID) { $staff_id = mysql_real_escape_string($staffID); $attendance_status = mysql_real_escape_string($_POST[$staff_id . "_attendance_status"]); $notes = mysql_real_escape_string($_POST[$staff_id . "_notes"]); $sql .= mysql_query("INSERT INTO StaffAttendance (StaffID, AttendanceDate, AttendanceStatus, Notes) VALUES ('$staff_id', now(), '$attendance_status', '$notes')") or die (mysql_error()); $editid = mysql_insert_id(); } </code></pre>
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    1. POInserting multiple values from multiple forms at once in PHP and MySQL
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    1. COThank you for your comments. @Ben you're right, I should have been more specific. My problem was was that the data wasn't appearing at the back end database. David-SkyMesh and Stefan that's great thanks, I'll have a look now and let you know if it works! Many thanks, Zulu
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    2. CO@ZuluIrminger: OK - I have added some edits with more suggestions on how to do this.
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    3. COYou guys are amazingly helpful, I'm so grateful! I'll have a go at this in a minute. The way I tried it just now inserted 100,000 blank rows into my database... I'm currently waiting for php myadmin to load them all so I can delete them...!
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