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    <p>your first syntax error is because of having another <code>&lt;&lt;</code> at the end of statement <code>cout&lt;&lt;F&lt;&lt;;</code> just change it to <code>cout&lt;&lt;F;</code> unless you have another var to print or you want to use endline like: <code>cout&lt;&lt;F&lt;&lt;endl;</code>.</p> <p>you have another one syntax error too! your <code>main</code> returns int but you didn't returned anything at the end:</p> <p><code>return 0;</code></p> <p><strong>Another very very very important issue is about the variable <code>F</code>!</strong></p> <p><strong>Logical error!!!</strong></p> <pre><code>int main() { .... float S_dist; //real S_dist !!! float E_dist; //real E_dist !!! float F; //real F !!! for (t=0; t&lt;30000; t++) { float F; // just exists in for!!! float E_dist; //just exists in for!!! float E_dist; //just exists in for!!! .... F=(G*Me*Ms)/(r*r); //changing local F, which just exists in for E_dist=sqrt( ((pe[0]-pe[0])*(pe[0]-pe[0])) + ((pe[1]-pe[1])*(pe[1]-pe[1])) ); S_dist=sqrt( ((ps[0]-ps[0])*(ps[0]-ps[0])) + ((ps[1]-ps[1])*(ps[1]-ps[1])) ); } cout&lt;&lt;F&lt;&lt;E_dist&lt;&lt;S_dist; //this prints the main vars! return 0; } </code></pre> <p>be sure to read about local variables more. and keep in mind that <code>t+1</code> doesn't change the <code>t</code> at all! you should write <code>t++</code> or <code>t+=1</code> in the last part of the <code>for</code> statement instead! unless you will get an infinite loop, cause your <code>t</code> does not grow at all!</p>
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