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    <p>Soory for my delay (i had other tasks).</p> <p>I solved that problem not with proposed libraries (with simple javascript), but exist another problem: when i changed country - select region changes automatically, but i can't save new region value (when another region from the same country - not problem), because error <strong>Select a valid choice. That choice is not one of the available choices.</strong></p> <p>Models are the same in first question, but default value for model country equal 1.</p> <p>My first way was change country select through formfield_key function, </p> <pre><code>def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == 'region': kwargs["queryset"] = Region.objects.filter(country=self.country) return db_field.formfield(**kwargs) </code></pre> <p>but i don't know is the saving objects, or editing objects.</p> <p><a href="https://stackoverflow.com/a/949290/1221313">Here</a> wrote - the best way is changing through form and now i have code:</p> <pre><code>class Item(models.Model): country = models.ForeignKey(Country, default=1) region = models.ForeignKey(Region, related_name='') class ItemAdmin(admin.ModelAdmin): form = CustomItemForm prepopulated_fields = {"alias": ("name",)} list_filter = ('country', 'category',) class CustomItemForm(forms.ModelForm): def __init__(self, *args, **kwargs): try: country = kwargs['instance'].country except KeyError: country = 1 super(CustomItemForm, self).__init__(*args, **kwargs) self.fields['region'].queryset = Region.objects.filter(country=country) </code></pre>
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    1. PODjango admin form - how to change dynamically select values
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    1. COI just solved this problem in one of my apps yesterday, see my answer below
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      1. USFrancis Yaconiello
    2. COalso, in your `__init__` method, if `kwargs['instance']` isnt set and throws an exception `country = 1` will throw an error in the `Region.objects.fitler(country=country)` line of code b/c filter expects an object instance not an int. just FYI that could fail
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      1. USFrancis Yaconiello
 

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