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POBuilding an array where each element depends on the previous
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2012-04-04T13:41:22.353
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I'm building a set of arrays where each element depends on the previous element, and I'm having a hard time coming up with an elegant solution for setting the initial value. The code looks something like this: <pre><code>int A[1024]; int B[1024]; /* ... more arrays... */ int i; for (i = 0; i < 1024; i++) { /* do some work */ A[i] = A[i-1] + some_value(); B[i] = B[i-1] + some_other_value(); /* ... and so on... */ } </code></pre> But of course this is an invalid memory access when <code>i</code> is 0. I know that the initial values of all arrays should be 0. There are several ways to solve this problem. I could put a giant <code>if</code> statement in the loop to check if <code>i</code> is 0. Seems clunky since it will only evaluate to <code>true</code> once. I could keep a temporary variable, initialized to 0, for each array, called <code>prev_val_of_A</code>, etc, that holds the value of the last iteration. I'd have to update it to the current value at the end of every iteration. This seems a little silly since, most of the time, the value I want is sitting right there in the array's previous element. I could fiddle with the meaning of the array, and adopt the convention that the second element in the array contains the value for the first iteration of the loop; that is, allocate for <code>A[1025]</code>, initialize <code>A[0]</code>, then in the loop, do <pre><code>A[i+1] = A[i] + some_value(); </code></pre> This seems confusing and might invite errors on further use of <code>A</code>. I'm looking for clean, elegant suggestions to solve this issue.
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Building an array where each element depends on the previous
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