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POOpen a path with Desktop.open() from java on ubuntu (linux)
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  1. POOpen a path with Desktop.open() from java on ubuntu (linux)
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    copied!<p>From my application written in java I want to open a folder, using the operating system file explorer.</p> <p>I use Desktop.open(new File(path))</p> <p>This works fine on windows, but on ubuntu 11.10 (linux) it doesn't work. Using the Desktop.open to open a file does work, both on ubuntu and windows.</p> <p>Using a step in between: File fPath=new File(fPath) and testing it with fPath.exists() and fPath.isDirectory() both gives true.</p> <p>using the Desktop.open(new File(path)) gives me this exception:</p> <pre><code>java.io.IOException: Failed to show URI:file:/and/here/the/path/I/use/ at sun.awt.X11.XDesktopPeer.launch(Unknown Source) at sun.awt.X11.XDesktopPeer.open(Unknown Source) at java.awt.Desktop.open(Unknown Source) </code></pre> <p>I was not able to test this on an apple computer yet, but I hoped the Desktop.open(new File(path)) was system independent.....</p> <p>by the way, the complete code:</p> <pre><code> Desktop desktop = null; // Before more Desktop API is used, first check // whether the API is supported by this particular // virtual machine (VM) on this particular host. if (!Desktop.isDesktopSupported()) { // show Error return; } desktop = Desktop.getDesktop(); String path = "here the path "; // by the way: I use System.getProperty("file.separator") as file seperator try { File fPath=new File(path); if(!fPath.exists()){ // show Error return; } if(!fPath.isDirectory()){ // show Error return; } desktop.open(new File(path)); } catch (IOException e) { log.severe(e.getMessage()); e.printStackTrace(); // show Error return; } </code></pre> <p>Some extra information: OS: Linux (3.0.0-16-generic - amd64)</p> <p>Java: 1.6.0_30-b12</p> <p>Java home: /opt/java/64/jre1.6.0_30</p>
 

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