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POHow do I get the exit code via %errorlevel% , its not working anymore with assembly program
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copied!<p>I want to get the exit code of my tutorial assembly program (using masm32 and link). It was working fine, I would type echo <code>%errorlevel%</code> and it would display my exit code that I typed in after <code>invoke ExitProcess</code>. Now it doesn't work anymore. I'm using VirtualBox on an OpenSuse 12.1 host and Windows Vista Home Premium as the guest. I've searched for answers but have come up short. Most complaints are about using a batch file, which is not what I'm trying to do. Here is the simple program</p> <p><strong>hello_world.asm</strong></p> <pre><code>.586 .model flat, stdcall option casemap :none include \masm32\include\windows.inc include \masm32\include\kernel32.inc include \masm32\include\user32.inc includelib \masm32\lib\kernel32.lib includelib \masm32\lib\user32.lib .data HelloWorld db "Hello World!", 0 .code start: invoke MessageBox, NULL, addr HelloWorld, addr HelloWorld, MB_OK invoke ExitProcess, 2 end start </code></pre> <p>I expect it to return 2, but <code>echo %errorlevel%</code> returns 0. Is there something I'm missing? Thanks, and I apologize this question has been answered to death. I just can't find my answer.</p> <p><strong>Edit</strong>: Actually, I found part of my answer. It only works if I link using <code>/SUBSYSTEM:CONSOLE</code>. Using <code>/SUBSYSTEM:WINDOWS</code> always returns 0. I don't know what to make of this. where is the exit code with a windows program? any info greatly appreciated.</p>

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