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POSharpGL & Kinect - Rendering ColorImageFrame Bitmap to OpenGL Texture
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  1. POSharpGL & Kinect - Rendering ColorImageFrame Bitmap to OpenGL Texture
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    copied!<p>I want to draw a simple 2D quad with a texture from the Kinect's video input but my code isn't working.</p> <p>Here is my ColorFrameReady event:</p> <pre><code> void Sensor_ColorFrameReady(object sender, ColorImageFrameReadyEventArgs e) { ColorImageFrame cif = e.OpenColorImageFrame(); if (cif != null) { middleBitmapSource = cif.ToBitmapSource(); cif.Dispose(); } } </code></pre> <p>This is my OpenGL draw method:</p> <pre><code> private void OpenGLControl_OpenGLDraw(object sender, OpenGLEventArgs args) { // Get the OpenGL instance being pushed to us. gl = args.OpenGL; // Clear the colour and depth buffers. gl.Clear(OpenGL.GL_COLOR_BUFFER_BIT | OpenGL.GL_DEPTH_BUFFER_BIT); // Enable textures gl.Enable(OpenGL.GL_TEXTURE_2D); // Reset the modelview matrix. gl.LoadIdentity(); // Load textures if (middleBitmapSource != null) { middleBitmap = getBitmap(middleBitmapSource, quadMiddleWidth, quadMiddleHeight); //middleBitmap = new System.Drawing.Bitmap("C:\\Users\\Bobble\\Pictures\\Crate.bmp"); // When I use this texture, it works fine gl.GenTextures(1, textures); gl.BindTexture(OpenGL.GL_TEXTURE_2D, textures[0]); gl.TexImage2D(OpenGL.GL_TEXTURE_2D, 0, 3, middleBitmap.Width, middleBitmap.Height, 0, OpenGL.GL_BGR, OpenGL.GL_UNSIGNED_BYTE, middleBitmap.LockBits(new System.Drawing.Rectangle(0, 0, middleBitmap.Width, middleBitmap.Height), System.Drawing.Imaging.ImageLockMode.ReadOnly, System.Drawing.Imaging.PixelFormat.Format24bppRgb).Scan0); gl.TexParameter(OpenGL.GL_TEXTURE_2D, OpenGL.GL_TEXTURE_MIN_FILTER, OpenGL.GL_LINEAR); gl.TexParameter(OpenGL.GL_TEXTURE_2D, OpenGL.GL_TEXTURE_MAG_FILTER, OpenGL.GL_LINEAR); } // Move back a bit gl.Translate(0.0f, 0.0f, -25.0f); gl.BindTexture(OpenGL.GL_TEXTURE_2D, textures[0]); // Draw a quad. gl.Begin(OpenGL.GL_QUADS); // Draw centre quad gl.TexCoord(0.0f, 0.0f); gl.Vertex(-(quadMiddleWidth / 2), quadMiddleHeight / 2, quadDepthFar); gl.TexCoord(0.0f, 1.0f); gl.Vertex(quadMiddleWidth / 2, quadMiddleHeight / 2, quadDepthFar); gl.TexCoord(1.0f, 1.0f); gl.Vertex(quadMiddleWidth / 2, -(quadMiddleHeight / 2), quadDepthFar); gl.TexCoord(1.0f, 0.0f); gl.Vertex(-(quadMiddleWidth / 2), -(quadMiddleHeight / 2), quadDepthFar); gl.End(); gl.Flush(); } </code></pre> <p>And here is a helper method which converts a BitmapSource to a Bitmap of a given size:</p> <pre><code> private System.Drawing.Bitmap getBitmap(BitmapSource bitmapSource, double rectangleWidth, double rectangleHeight) { double newWidthRatio = rectangleWidth / (double)bitmapSource.PixelWidth; double newHeightRatio = ((rectangleWidth * bitmapSource.PixelHeight) / (double)bitmapSource.PixelWidth) / (double)bitmapSource.PixelHeight; BitmapSource transformedBitmapSource = new TransformedBitmap(bitmapSource, new ScaleTransform(newWidthRatio, newHeightRatio)); int width = transformedBitmapSource.PixelWidth; int height = transformedBitmapSource.PixelHeight; //int stride = width * ((transformedBitmapSource.Format.BitsPerPixel + 7) / 8); int stride = ((width * transformedBitmapSource.Format.BitsPerPixel + 31) &amp; ~31) / 8; // See: http://stackoverflow.com/questions/1983781/why-does-bitmapsource-create-throw-an-argumentexception/1983886#1983886 byte[] bits = new byte[height * stride]; transformedBitmapSource.CopyPixels(bits, stride, 0); unsafe { fixed (byte* pBits = bits) { IntPtr ptr = new IntPtr(pBits); System.Drawing.Bitmap bitmap = new System.Drawing.Bitmap( width, height, stride, System.Drawing.Imaging.PixelFormat.Format32bppArgb, ptr); return bitmap; } } } </code></pre> <p>The quad renders but it is just white, no texture on it.</p>
 

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