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POPOSTing a file and passing a parameter using pycurl
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  1. POPOSTing a file and passing a parameter using pycurl
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    copied!<p>I have figured out how to do GET, PUTs, DELETEs and basic POST using pycurl.</p> <p>Nevertheless, I can't figure out what is the equivalent of this curl command line (which works perfectly fine) to python:</p> <pre><code>curl -u admin:geoserver -XPOST -H 'Content-type: application/vnd.ogc.sld+xml' -d @/Users/rburhum/src/calthorpe/calthorpe/server/calthorpe/media/styles/1_my-scenario "http://127.0.0.1:8080/geoserver/rest/styles?name=1_my-scenario" -v </code></pre> <p><a href="http://pycurl.cvs.sourceforge.net/viewvc/pycurl/pycurl/tests/test_post.py?revision=1.9&amp;view=markup" rel="nofollow">I have seen the samples at the repo</a>. Nevertheless, passing one parameter (in this case <em>name</em>) and a file to be uploaded doesn't seem to work.</p> <p>For PUT calls, I have successfully used:</p> <pre><code>filesize = path.getsize(sldFile) f = open(sldFile,'rb') c = pycurl.Curl() c.setopt(pycurl.HTTPHEADER, ["Content-type: application/vnd.ogc.sld+xml"]) c.setopt(pycurl.USERPWD, GEOSERVER_USER + ':' + GEOSERVER_PASSWORD) c.setopt(pycurl.INFILESIZE, filesize) c.setopt(c.URL, str(GEOSERVER_URL + '/rest/styles/' + path.basename(sldFile))) c.setopt(pycurl.PUT, 1) c.setopt(pycurl.INFILE, f) c.perform() f.close() </code></pre> <p>thus, I naively thought that the POST equivalent would be:</p> <pre><code>filesize = path.getsize(sldFile) f = open(sldFile,'rb') c = pycurl.Curl() c.setopt(c.URL, str(GEOSERVER_URL + '/rest/styles?name=' + path.basename(sldFile))) c.setopt(pycurl.POST, 1) c.setopt(pycurl.HTTPHEADER, ["Content-type: application/vnd.ogc.sld+xml"]) c.setopt(pycurl.USERPWD, GEOSERVER_USER + ':' + GEOSERVER_PASSWORD) c.setopt(pycurl.INFILESIZE, filesize) c.setopt(pycurl.INFILE, f) c.perform() f.close() </code></pre> <p>The verbose output of the curl command displays this:</p> <p>(calthorpe_env)rburhum@peru.local ~/src/calthorpe/calthorpe/server/calthorpe $calthorpe/server/calthorpe POST -H 'Content-type: application/vnd.ogc.sld+xml' -d@/Users/rburhum/src/calthorpe/calthorpe/server/calthorpe/media/styles/1_my-scenario "http://127.0.0.1:8080/geoserver/rest/styles?name=1_my-scenario" -v * About to connect() to 127.0.0.1 port 8080 (#0) * Trying 127.0.0.1... connected * Connected to 127.0.0.1 (127.0.0.1) port 8080 (#0) * Server auth using Basic with user 'admin'</p> <blockquote> <p>POST /geoserver/rest/styles?name=1_my-scenario HTTP/1.1 Authorization: Basic YWRtaW46Z2Vvc2VydmVy User-Agent: curl/7.21.4 (universal-apple-darwin11.0) libcurl/7.21.4 OpenSSL/0.9.8r zlib/1.2.5 Host: 127.0.0.1:8080 Accept: <em>/</em> Content-type: application/vnd.ogc.sld+xml Content-Length: 28135 Expect: 100-continue</p> </blockquote> <p>  > &lt; HTTP/1.1 100 Continue &lt; HTTP/1.1 201 Created &lt; Date: Mon, 05 Mar 2012 07:39:43 GMT &lt; Location: <a href="http://127.0.0.1:8080/geoserver/rest/styles/1_my-scenario" rel="nofollow">http://127.0.0.1:8080/geoserver/rest/styles/1_my-scenario</a> &lt; Server: Noelios-Restlet-Engine/1.0..8 &lt; Transfer-Encoding: chunked &lt; * Connection #0 to host 127.0.0.1 left intact * Closing connection #0</p> <p>I can clearly see that the content length is correct.</p> <p>In contrast, when I do a verbose output of my POST code above, I can see that the content length is -1 (and hence the file is not being passed and the server gives back a 500). I have mocked with the HTTPPOST variable, which under certain combinations makes the content length be correct, but I still cannot get the exact equivalent of the CURL command above to work.</p>
 

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