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copied!<blockquote> <p>but what I want to get is child without namespace declaration from parent xmlns="default_ns".</p> </blockquote> <p><strong>This is not possible to achieve by only evaluating an XPath expression.</strong></p> <p><strong>In XML any element inherits all of its parent's namespace nodes</strong>, unless it redefines a particular namespace.</p> <p><strong>This means that <code>some_prefix:a</code> inherits the default namespace <code>"default_ns"</code></strong> from its parent (<code>subelement</code>), which itself inherits this same default namespace node from the top element <code>root</code>.</p> <p>XPath is a query language for XML documents. As such, it only helps select nodes, but <strong>the evaluation of an XPath expression never destroys, adds or alters nodes, including namespace nodes</strong>.</p> <p>Because of this, the default namespace node that belongs to <code>some_prefix:a</code> cannot be destroyed as result of the evaluation of your XPath expression -- thus this namespace node is shown when <code>some_prefix:a</code> is serialized to text.</p> <p><strong>Solution</strong>: Use your favorite PL that hosts XPath, to delete the unwanted namespace node.</p> <p><strong>For example, if the hosting language is XSLT</strong>:</p> <pre><code><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:d="default_ns"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:template match="/"> <xsl:apply-templates mode="delNS" select="/*/d:subelement/*[1]"/> </xsl:template> <xsl:template match="*" mode="delNS"> <xsl:element name="{name()}" namespace="{namespace-uri()}"> <xsl:copy-of select="namespace::*[name()]"/> <xsl:copy-of select="@*"/> <xsl:apply-templates mode="delNS" select="node()"/> </xsl:element> </xsl:template> </xsl:stylesheet> </code></pre> <p><strong>when this transformation is applied on the provided XML document</strong>:</p> <pre><code><root xmlns="default_ns"> <subelement>  <some_prefix:a xmlns:some_prefix="some_namespace"> <some_prefix:b/> </some_prefix:a> </subelement> </root> </code></pre> <p><strong>the wanted, correct result is produced</strong>:</p> <pre><code><some_prefix:a xmlns:some_prefix="some_namespace"> <some_prefix:b/> </some_prefix:a> </code></pre>

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