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copied!<p>Your problem here is scope - <code>exit</code> is local to the function <code>exit()</code> so doesn't affect the variable <code>exit</code> in the loop scope.</p> <p>A better solution is this:</p> <pre><code>exit = False while not exit: option = raw_input("What would you like to do?") if option == "exit": exit = True </code></pre> <p>Or simply:</p> <pre><code>while True: option = raw_input("What would you like to do?") if option == "exit": break </code></pre> <p>Note the use of <code>True</code> and <code>False</code> over <code>1</code> and <code>0</code> - this is more pythonic, as what you mean here is truth values, not integers. I also changed to compare to the string <code>"exit"</code>, as I presumed that was what you wanted, not comparing the user input to the value of <code>exit</code>.</p> <p>If your problem is you want to have the same scope, you might want to make your code part of a class.</p> <pre><code>class Doer: #Naturally, give it a real name based on it's purpose. def __init__(self): self.exit = False while not self.exit: option = raw_input("What would you like to do?") if option == "exit": self.exit() def exit(self): self.exit = True </code></pre> <p>Here <code>exit</code> is an instance variable (hence being accessed from <code>self</code>) and therefore both times we are referencing the same variable.</p> <p>If your code is not a simplification of a more complex problem, this is largely overkill, as one of the first solutions would be more appropriate.</p>

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