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copied!<p>Your assumptions are wrong.</p> <blockquote> <p>I understand that "__get called!" appears when $employee->name is accesed</p> </blockquote> <p>No, it doesn't. <code>__get</code> is only invoked when you attempt to access a member which <em>does not exist</em>. You have defined a publicly accessible member named <code>$name</code>, this is what the line <code>var $name</code> does. Reading/writing to <code>$employee->name</code> will <em>never</em> invoke the magic <code>__get</code> or <code>__set_</code> methods.</p> <p>It is not <code>$employee->name</code> that is causing <code>"__get called"</code> to be printed; <code>$employee->name</code> is returning <code>"Mario"</code>, the value you assigned to that member, and <em>that</em> is what is being printed. It is <code>$employee->age</code> that is causing <code>"__get called"</code> to be printed.</p> <p>I've tried to better explain the lines and what they do in respect to <code>__get</code>:</p> <pre><code>$employee = new Employee(); $employee->name = "Mario"; # assign to $name echo $employee->name."<br />"; # read "Mario" from $name, does NOT invoke __get echo $employee->age; # attempt to read $age, invokes __get </code></pre> <p>RE: Your observation</p> <blockquote> <p>Observation : Of course __get runs when it detects $age does not exist when read, but ...when it does run, why doesn't the echo in it work?</p> </blockquote> <p>The echo <em>does</em> work. The reason you are only seeing one <code>"__get called!"</code> is because <code>__get</code> is only called once, by attempting to access <code>$employee->age</code>.</p>

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