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copied!<p>Your question makes no sense. Pointers, by definition, are a memory address to something - the size must depend upon the platform. How would you dereference a 128-bit pointer on a hardware platform supporting 64-bit addressing?!</p> <p>You can create 64 or 128-bit <em>values</em>, but a pointer is directly related to the memory addressing scheme of the underlying hardware.</p> <p>EDIT</p> <p>With your additional statement, I think I see what you're trying to do. Unfortunately, I doubt it's possible. If the kernel function you want to use takes a 64-bit pointer argument, it's highly likely to be a 64-bit function (unless you're developing for some unusual hardware). </p> <p>Even though it's <em>technically</em> possible to mix 64-bit instructions into a 32-bit executable, no compiler will actually let you do this. A 64-bit API call will use 64-bit code, 64-bit registers and a 64-bit stack - it would be extremely awkward for the compiler and operating system to manage arbitrary switching from a 32-bit environment to a 64-bit environment.</p> <p>You should look at finding the equivalent API for a 32-bit environment. Perhaps you could post the kernel function prototype (name+parameters) you want to use and someone could help you find a better solution.</p> <p>Just so there's no confusion, <code>__ptr64</code> in MSDN is <em>not</em> platform independent: </p> <blockquote> <p>On a 32-bit system, a pointer declared with __ptr64 is truncated to a 32-bit pointer.</p> </blockquote>

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