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copied!<pre><code>np.array(list(set(map(tuple, input)))) </code></pre> <p>returns</p> <pre><code>array([[4, 5], [2, 3], [1, 1]]) </code></pre> <p><strong>UPDATE 1:</strong> If you want to remove the <code>[1, 1]</code> too (because it appears more than once), you can do:</p> <pre><code>from collections import Counter np.array([k for k, v in Counter(map(tuple, input)).iteritems() if v == 1]) </code></pre> <p>returns</p> <pre><code>array([[4, 5], [2, 3]]) </code></pre> <p><strong>UPDATE 2:</strong> with <code>input=[[1,1,2], [1,1,3], [2,3,4], [4,5,5], [1,1,7]]</code>:</p> <pre><code>input=[[1,1,2], [1,1,3], [2,3,4], [4,5,5], [1,1,7]] d = {} for a in input: d.setdefault(tuple(a[:2]), []).append(a[2]) </code></pre> <p><code>d</code> is now:</p> <pre><code>{(1, 1): [2, 3, 7], (2, 3): [4], (4, 5): [5]} </code></pre> <p>so we want to take all key-value pairs, that have single values and re-create the arrays:</p> <pre><code>np.array([k+tuple(v) for k,v in d.iteritems() if len(v) == 1]) </code></pre> <p>returns:</p> <pre><code>array([[4, 5, 5], [2, 3, 4]]) </code></pre> <p><strong>UPDATE 3:</strong> For larger arrays, you can adapt my previous solution to:</p> <pre><code>import numpy as np input = [[1,1,3,5,6,6],[1,1,4,4,5,6],[1,3,4,5,6,7],[3,4,6,7,7,6],[1,1,4,6,88,7],[3,3,3,3,3,3],[456,6,5,343,435,5]] d = {} for a in input: d.setdefault(tuple(a[:2]), []).append(a) np.array([v for v in d.itervalues() if len(v) == 1]) </code></pre> <p>returns:</p> <pre><code>array([[[456, 6, 5, 343, 435, 5]], [[ 1, 3, 4, 5, 6, 7]], [[ 3, 4, 6, 7, 7, 6]], [[ 3, 3, 3, 3, 3, 3]]]) </code></pre>

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