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copied!<p>Simply using $data['country'] will not work because the given result is not an object or array. You need to split the content into an array or, even better, retrieve it as a JSON object and then use:</p> <pre><code>$data = json_decode($data); </code></pre> <p>To give you the data in an array.</p> <p><strong>Despite the above, I wouldn't advise getting locations from IP Addresses because it is incredibly inaccurate! It returns the location of the Host server, not necessarily the location of the user.</strong></p> <p><strong>EDIT:</strong></p> <p>Use the JSON API: <a href="http://ipinfodb.com/ip_location_api_json.php" rel="nofollow">http://ipinfodb.com/ip_location_api_json.php</a></p> <p><strong>Update:</strong></p> <p>Steps to implementing the JSON API:</p> <ol> <li>Register for an API key here: <a href="http://ipinfodb.com/register.php" rel="nofollow">http://ipinfodb.com/register.php</a>. This will allow you to retrieve results from their server, without this it will not work.</li> <li>You do not need to implement any SDK to get this to work, so all you should need is this:</li> </ol> <p>Copy and past the following PHP code:</p> <pre><code>// Set the parameters $ip_address = $_SERVER['REMOTE_ADDR']; $api_key = 'YOUR_API_KEY_HERE'; // Get the data $data = file_get_contents("http://api.ipinfodb.com/v3/ip-city/?key=$api_key&ip=$ip_address&format=json"); // Decode the JSON result into an array $data = json_decode($data); // All data can now be accessed using the associative array $data $country = $data['Country']; // Country $city = $data['City']; // City </code></pre>

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