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POArray of 2d arrays
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copied!<p>My question is difficult to describe, and I have two tables containing lots of numbers respectively; for one table, I search format through index </p> <pre><code>table1 index format +------+----+ |0~19 | 0 | | | | +------+----+ |20~29 | 1 | | | | +------+----+ |30~39 | 2 | | | | +------+----+ table2 index resource(f,t0,t1,t2) 0 1 2 3 (configure type) +----+-----------+---------+---------+ |0 | (0,1,0,2) |(0,1,0,1)|(0,1,0,0)| +----+-----------+---------+---------+ |1 | (0,2,0,2) |(0,2,0,1)|(0,2,0,0)| +----+-----------+---------+---------+ |-- | (0,0,1,2) |(0,0,1,1)|(1,0,0,0)| +----+-----------+---------+---------+ |19 | (0,0,0,0) |(0,0,0,0)|(0,0,1,1)| +----+-----------+---------+---------+---------+ |-- | (0,0,0,2) |(0,0,0,1)|(0,0,1,0)|(0,2,1,0)| +----+-----------+---------+---------+---------+ |29 | (0,1,0,2) |(0,1,0,1)|(0,1,0,1)|(0,1,0,1)| +----+-----------+---------+---------+---------+ </code></pre> <p>Hopefully,the following code snippet can make me understood,</p> <pre><code>typedef struct my_struct { int f; int t0; int t1; int t2; } my_struct; // for index 0 ~ 19, the following is code snippet my_struct format0[2][3] = { {{0, 1, 0, 2}, {0, 1, 0, 1},{0, 1, 0, 0}}, // index 0 {{0, 2, 0, 2}, {0, 2, 0, 1},{0, 2, 0, 0}} // index 1 }; // for index 20 ~ 29, the following is code snippet my_struct format1[1][4] = { {{0,0,0,2},{0,0,0,1},{0,0,1,0},{0,2,1,0}} // index 20 }; </code></pre> <p>I have multiple 2d arrays containing resources grouped by <code>format</code>, each has different dimensions for different <code>format</code>, rowed by <code>index</code>, coled by <code>configure type</code> like 0,1,2..6, so I want to put them into another 1d array in order to look up easily through index, and get resource finally, but I don't know how.</p> <p>I have tried the following but failed:</p> <pre><code>my_struct* group[] = { format0, format1 }; </code></pre> <p>then using <code>group[0]</code>, I can get <code>format0</code>, but I find it forgot its <code>[1][2]</code> which I need to know, so I am wondering there is some solution help me do that?</p>

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