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copied!<p>In response to the updated constraints, one solution is to pin A and X, and then lay out the graph around them:</p> <pre><code>graph sample { overlap=false; splines=true; tailclip=false; headclip=false; A [pin=true,pos="0,.2"] X [pin=true,pos="0,.1"] A -- I A -- J A -- B A -- H A -- E A -- K B -- D B -- C B -- L C -- M C -- N C -- O D -- P D -- Q E -- R F -- A G -- F H -- J A -- X </code></pre> <p><img src="https://i.stack.imgur.com/YSFCM.png" alt="graph output"></p> <p>I tried layout with both neato and fdp, and it seems to produce a graph like what you want. Naturally, if you want to impose such a constraint on arbitrary pairs of nodes in the same graph, this solution may not work.</p> <p>--- Earlier answer ---</p> <p>If you're committed to using neato, I'm not certain there is a way to solve the problem without modifying the graph in a post-processing step. If neato is just a convenient default, then you should be able to solve your problem by using dot as your layout engine instead, and using "rankdir=UD", plus a couple of additional kludges if X needs to be due south.</p> <p>In the event that you only need the constraint to apply for a single node X, then putting X and A together in a cluster should do the job:</p> <pre><code>graph sample { rankdir=UD layout=dot overlap=false // .. as before A -- X subgraph clusterone { style=invisible A X } } </code></pre> <p>If you need a strictly-south constraint to apply to arbitrary children of A, then that kind of clustering followed by the trick described in:</p> <p><a href="https://stackoverflow.com/questions/1476241/how-to-force-all-nodes-in-the-same-column-in-graphviz">How to force all nodes in the same column in graphviz?</a></p> <p>might do the trick. The attribute <code>clusterrank=local</code> might also be useful in that case, but I'm not certain. Hope this helps.</p>

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