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POWhy does g++ complain when using templated typedefs in graph_traits<>?
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  1. POWhy does g++ complain when using templated typedefs in graph_traits<>?
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    copied!<p>When I try to compile this code:</p> <pre><code>struct BasicVertexProperties { Vect3Df position; }; struct BasicEdgeProperties { }; template &lt; typename VERTEXPROPERTIES, typename EDGEPROPERTIES &gt; class Graph { typedef adjacency_list&lt; setS, // disallow parallel edges vecS, // vertex container bidirectionalS, // directed graph property&lt;vertex_properties_t, VERTEXPROPERTIES&gt;, property&lt;edge_properties_t, EDGEPROPERTIES&gt; &gt; GraphContainer; typedef graph_traits&lt;GraphContainer&gt;::vertex_descriptor Vertex; typedef graph_traits&lt;GraphContainer&gt;::edge_descriptor Edge; }; </code></pre> <p>g++ complains with the following error in the "typedef graph_traits&lt;>" line:</p> <pre><code>error: type 'boost::graph_traits&lt;boost::adjacency_list&lt;boost::setS, boost::vecS, boost::bidirectionalS, boost::property&lt;vertex_properties_t, VERTEXPROPERTIES, boost::no_property&gt;, boost::property&lt;edge_properties_t, EDGEPROPERTIES, boost::no_property&gt;, boost::no_property, boost::listS&gt; &gt;' is not derived from type 'Graph&lt;VERTEXPROPERTIES, EDGEPROPERTIES&gt;' </code></pre> <p>I found out that the compiler seems not to know that my template parameters are types, but putting "typename" before them in the property definition doesn't help.</p> <p>What is wrong? I simply want to have a templated Graph class to have the possibility to use whatever properties I like, derived from the basic property structs defined above, so I can have methods in this Graph that operate on the basic properties.</p>
 

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