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POHow do I encode/decode UTF-16LE byte arrays with a BOM?
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  1. POHow do I encode/decode UTF-16LE byte arrays with a BOM?
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    copied!<p>I need to encode/decode UTF-16 byte arrays to and from <code>java.lang.String</code>. The byte arrays are given to me with a <a href="http://unicode.org/faq/utf_bom.html#bom1" rel="noreferrer">Byte Order Marker (BOM)</a>, and I need to encoded byte arrays with a BOM.</p> <p>Also, because I'm dealing with a Microsoft client/server, I'd like to emit the encoding in little endian (along with the LE BOM) to avoid any misunderstandings. I do realize that with the BOM it should work big endian, but I don't want to swim upstream in the Windows world.</p> <p>As an example, here is a method which encodes a <code>java.lang.String</code> as <code>UTF-16</code> in little endian with a BOM:</p> <pre><code>public static byte[] encodeString(String message) { byte[] tmp = null; try { tmp = message.getBytes("UTF-16LE"); } catch(UnsupportedEncodingException e) { // should not possible AssertionError ae = new AssertionError("Could not encode UTF-16LE"); ae.initCause(e); throw ae; } // use brute force method to add BOM byte[] utf16lemessage = new byte[2 + tmp.length]; utf16lemessage[0] = (byte)0xFF; utf16lemessage[1] = (byte)0xFE; System.arraycopy(tmp, 0, utf16lemessage, 2, tmp.length); return utf16lemessage; } </code></pre> <p>What is the best way to do this in Java? Ideally I'd like to avoid copying the entire byte array into a new byte array that has two extra bytes allocated at the beginning.</p> <p>The same goes for decoding such a string, but that's much more straightforward by using the <a href="http://file:///Users/jared/Documents/jdk-6u10-docs/api/java/lang/String.html#String(byte[],%20int,%20int,%20java.lang.String)" rel="noreferrer"><code>java.lang.String</code> constructor</a>:</p> <pre><code>public String(byte[] bytes, int offset, int length, String charsetName) </code></pre>
 

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