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copied!<p>Since you say its not homework, and I'm a trusting fellow...</p> <ol> <li><p>Build a new array of variable-operator combinations by running each variable against the operator array => ["a+", "a-", "a*", "a/", "b+" ... "d/"]. We'll call this BuiltArray1</p></li> <li><p>Run this array against the operators, outputing each and also storing each in a new array => ["a+a", "a+b", "a+c", "a+d", "a-a" ..."d/d"]. We'll call this BuiltArray2. We can delete the original variable array ["a, "b", "c", "d"] now if we care to - we won't use it again.</p></li> <li><p>Now things get more fun... now we are building BuiltArray3. Run each item in BuiltArray1 against each item in BuiltArray2, outputting each and storing each in BuiltArray3 => ["a+a+a", "a-a+a", "a*a+a", "a/a+a", "b+a+a" ... "d/d/d"]. We can now delete BuiltArray2 to save some memory (this will start to consume memory quickly!)</p></li> <li><p>For BuiltArray4 until our computer dies screaming on the last BuiltArray_n it can handle, we run each item in BuiltArray1 against the previously built array, outputting and also storing each result in a new array, then deleting the previous array.</p></li> </ol> <p>This will chew through memory and processing power, but I can't think of anything more graceful off of the top of my head. </p> <p>Hope it helps.</p> <hr> <p>Here's Ruby codez:</p> <pre><code>@arr1 = ["a", "b", "c", "d"] arr2 = ["+", "-", "*", "/"] @base = [] @arr1.each do |char| arr2.each do |op| @base << char + op end end @right_vals = @arr1 loop do @new_values = [] @base.each do |left| @right_vals.each do |right| val = left + right puts val @new_values << val end end @right_vals = @new_values end </code></pre>

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