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copied!<p>The answer is no, according to the Java language specification, below. See the <strong>bold</strong> text.</p> <blockquote> <p>Assignment of a value of compile-time reference type S (source) to a variable of compile-time reference type T (target) is checked as follows: </p> <p>If S is a class type:</p> <ul> <li><strong>If T is a class type, then S must either be the same class as T, or S must be a subclass of T, or a compile-time error occurs.</strong></li> <li>If T is an interface type, then S must implement interface T, or a compile-time error occurs.</li> <li>If T is an array type, then a compile-time error occurs. </li> </ul> <p>If S is an interface type: </p> <ul> <li>If T is a class type, then T must be Object, or a compile-time error occurs. </li> <li>If T is an interface type, then T must be either the same interface as S or a superinterface of S, or a compile-time error occurs. </li> <li>If T is an array type, then a compile-time error occurs. </li> </ul> <p>If S is an array type SC[], that is, an array of components of type SC: </p> <ul> <li>If T is a class type, then T must be Object, or a compile-time error occurs. </li> <li>If T is an interface type, then a compile-time error occurs unless T is the type java.io.Serializable or the type Cloneable, the only interfaces implemented by arrays. </li> <li><p>If T is an array type TC[], that is, an array of components of type TC, then a compile-time error occurs unless one of the following is true: </p> <ul> <li>TC and SC are the same primitive type. </li> <li>TC and SC are both reference types and type SC is assignable to TC, as determined by a recursive application of these compile-time rules for assignability.</li> </ul></li> </ul> </blockquote>

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