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POHow to write this JavaScript code without eval (QUnit mocking)?
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  1. POHow to write this JavaScript code without eval (QUnit mocking)?
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    copied!<p>I've been experimenting with QUnit tests and was looking for a good method to override functions with mocks so as to enable more atomic tests. There are good solutions out there for specific cases, for example overriding $.ajax (<a href="https://gist.github.com/1371254" rel="nofollow">Simple jQuery (1.5+) AJAX Mocking</a>), but I was looking for a more general approach and came up with this:</p> <pre><code>// Constructor for overrides. function overrides(overrides) { this.overrides = overrides; } // Implementation for overrides. overrides.prototype = { set: function () { var functions = {}; $.each(this.overrides, function (key, value) { eval("functions['" + key + "'] = " + key + ";"); eval(key + " = value;"); }); this.functions = functions; }, reset: function () { var functions = this.functions; $.each(this.overrides, function (key, _) { eval(key + " = functions['" + key + "'];"); }); } } </code></pre> <p>Which can then be used like:</p> <pre><code>module("Comments", { setup: function () { this.overrides = new overrides({ "$.ajax": function (url, options) { alert("ajax: " + url + ', ' + options); } }); this.overrides.set(); }, teardown: function () { this.overrides.reset(); } }); </code></pre> <p>Now, that all appears to work fine, and although this may not be the worst possible use of eval(), I was wondering if this could indeed be written without using eval()? I've read up on a bunch of the other eval() questions here and tried various options like accessing the overrides using window[] but that does not work for the $.ajax case for example (window['$'].ajax works but not window['$.ajax']).</p> <p>Perhaps I'm also thinking to hard and eval() can be used safely here or there is a better approach in general for function overrides?</p>
 

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