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copied!<blockquote> <p>The code below selects the table but starting from most outer table. I need to select most inner table which contains that given string</p> </blockquote> <p><strong>Use</strong>:</p> <pre><code>//table [not(descendant::table) and .//text()[contains(., ' KDV')] ] </code></pre> <p>This selects any <code>table</code> in the XML document that doesn't have a <code>table</code> descendant, and that has a text node descendant that contains the string <code>" KDV"</code> .</p> <p>In general the above expression could select many such <code>table</code> elements.</p> <p><strong>If you want only one of them selected (say the first), use this XPath expression -- do notice the brackets</strong>:</p> <pre><code> (//table [not(descendant::table) and .//text()[contains(., ' KDV')] ] )[1] </code></pre> <p><strong>Remember</strong>: If you want to select the first <code>someName</code> element in the document, using this (as in the currently accepted answer) is wrong:</p> <pre><code>//someName[1] </code></pre> <p>This is the second most FAQ in XPath (after the one how to select elements with unprefixed names in an XML document with a default namespace).</p> <p>The expression above actually selects any <code>someName</code> element in the document, that is the first child of its parent -- try it.</p> <p>The reason for this unintuitive behavior is because the XPath <code>[]</code> operator has a higher precedence (priority) that the <code>//</code> pseudo-operator.</p> <p>The correct expression that really selects only the first <code>someName</code> element (in any XML document), if such exists is:</p> <pre><code>(//someName)[1] </code></pre> <p>Here the brackets are used to explicitly override the default XPath operator precedence.</p>

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