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copied!<p>How about following way of generating combinations using .Join method?</p> <pre><code>static void Main() { List<List<int>> collectionOfSeries = new List<List<int>> { new List<int>(){1, 2, 3, 4, 5}, new List<int>(){0, 1}, new List<int>(){6,3}, new List<int>(){1,3,5} }; int[] result = new int[collectionOfSeries.Count]; List<List<int>> combinations = GenerateCombinations(collectionOfSeries); Display(combinations); } </code></pre> <p>This Method <strong>GenerateCombinations(..)</strong> does main work of generating combinations. <strong>This method is generic so could be used for generating combinations of any type.</strong> </p> <pre><code>private static List<List<T>> GenerateCombinations<T>( List<List<T>> collectionOfSeries) { List<List<T>> generatedCombinations = collectionOfSeries.Take(1) .FirstOrDefault() .Select(i => (new T[]{i}).ToList()) .ToList(); foreach (List<T> series in collectionOfSeries.Skip(1)) { generatedCombinations = generatedCombinations .Join(series as List<T>, combination => true, i => true, (combination, i) => { List<T> nextLevelCombination = new List<T>(combination); nextLevelCombination.Add(i); return nextLevelCombination; }).ToList(); } return generatedCombinations; } </code></pre> <p>Display helper..</p> <pre><code>private static void Display<T>(List<List<T>> generatedCombinations) { int index = 0; foreach (var generatedCombination in generatedCombinations) { Console.Write("{0}\t:", ++index); foreach (var i in generatedCombination) { Console.Write("{0,3}", i); } Console.WriteLine(); } Console.ReadKey(); } </code></pre>

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