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copied!<p>[[Edit]]</p> <p>The attached method will not work if both target objects are leaf nodes in a shared parent.</p> <hr> <p>The timeline children are always under whatever actionscript generated children are associated to the timeline class.</p> <p>e.g.</p> <p>If you have timeline X, which extends ClassA, and in Class A, you add children E, F, G, but timeline X contains layers B, C, D, each with a single symbol in each layer, with layer B at the bottom of the timeline, the following would be observed:</p> <pre><code>child 5: G child 4: F child 3: E child 2: D child 1: C child 0: B </code></pre> <p>To expand on a felipemaia's answer, I've devised the following method to determine which movie clip lies absolutely above the other. This has not been thoroughly tested, but should operate as a baseline for your development.</p> <pre><code>function selectAbove(obj1:DisplayObject, obj2:DisplayObject):DisplayObject { var obj1_parentCount:int = parentCount(obj1); var obj2_parentCount:int = parentCount(obj2); var target:DisplayObject; var other:DisplayObject; if (obj1_parentCount > obj2_parentCount) { target = obj1; other = obj2; } else { target = obj2; other = obj1; } var container:DisplayObjectContainer = (target is DisplayObjectContainer) ? target as DisplayObjectContainer : target.parent ; var container_last:DisplayObjectContainer; var sharedParent:DisplayObjectContainer; while(container) { if(container.contains(other)) { sharedParent = container; break; } container_last = container; container = container.parent; } if(!sharedParent) { throw new Error("An object does not maintain its parent in the display heirarchy!"); } var ret:DisplayObject; if(container == other) { ret = target; } return container != other ? container.getChildIndex(container_last) < container.getChildIndex(other) ? other : target : target ; } function parentCount(obj:DisplayObject):int { var ret:int = 0; while(obj) { ret++; obj = obj.parent; } return ret; } </code></pre> <p>This method will work for nested display hierarchies. I have not tested this 100%, but initial cases completed as expected.</p> <p>Best of luck!</p>

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