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copied!<p>TF,</p> <p><strong>DISCLAIMER:</strong> This code is just off the top of my head... it hasn't even been compiled, let alone tested.</p> <pre><code>// returns the average of array[first..last] inclusive. int average(int[] array, int first, int last) { int sum = 0; for (i = first; i <= last; i++) sum += array[i]; return sum / (last - first + 1); // not sure about the +1 } </code></pre> <p>Then what you'd do is loop through the indexes of your <code>frequencyBar</code> array [0..7], setting <code>frequencyBar[i] = average(array, first, last);</code>... the tricky bit is calculating the <code>first</code> and <code>last</code> indexes... try <code>i*8</code> and <code>(i+1)*8</code> respectively... that may not be exactly right, but it'll be close ;-)</p> <p>Cheers. Keith.</p> <hr> <p><strong>EDIT:</strong> Bored... waiting for my test results to come back. No news is good news, right? ;-)</p> <p>It turns out that passing the <code>length</code> is a fair bit simpler than passing the <code>last</code> index.</p> <pre><code>#include <stdio.h> int sum(int array[], int first, int length) { int sum = 0; for (int i = first; i < first+length; i++) sum += array[i]; return sum; } double average(int array[], int first, int length) { double total = sum(array, first, length); #ifdef DEBUG printf("DEBUG: [%2d..%2d] %d", first, first+length-1, array[first]); for (int i = first+1; i < first+length; i++) printf(" + %d", array[i]); printf(" = %d / %d = %f\n", (int)total, length, total/length); #endif return total / length; } int main(int argc, char* argv[]) { int array[] = { // average 1, 2, 3, 4, 5, 1, 2, 3, // 2.625 4, 5, 1, 2, 3, 4, 5, 1, // 3.125 2, 3, 4, 5, 1, 2, 3, 4, // 3 5, 1, 2, 3, 4, 5, 1, 2, // 2.875 3, 4, 5, 1, 2, 3, 4, 5, // 3.375 1, 2, 3, 4, 5, 1, 2, 3, // 2.625 4, 5, 1, 2, 3, 4, 5, 1, // 3.125 2, 3, 4, 5, 1, 2, 3, 4 // 3 }; double frequency[8]; for (int i = 0; i < 8; i++) frequency[i] = average(array, i*8, 8); for (int i = 0; i < 8; i++) printf("%f ", frequency[i]); printf("\n"); } </code></pre>

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