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copied!<p>There are two types of arrays you should be able to distinguish. One looks like this:</p> <pre><code>type name[count]; </code></pre> <p>This array is of type <code>type[count]</code> which is a different type for each <code>count</code>. Although it is convertable to <code>type *</code>, it is different. One difference is that <code>sizeof(name)</code> gives you <code>count*sizeof(type)</code></p> <p>The other type of array looks like this:</p> <pre><code>type *name; </code></pre> <p>Which is basically just a pointer that you <em>could</em> initialize with an array for example with <code>malloc</code> or <code>new</code>. The type of this variable is <code>type *</code> and as you can see, there are no <em>count</em> informations in the type. Therefore, <code>sizeof(name)</code> gives you the size of a pointer in your computer, for example 4 or 8 bytes.</p> <p>Why are these two <code>sizeof</code>s different, you ask? Because <code>sizeof</code> is evaluated at compile time. Consider the following code:</p> <pre><code>int n; cin >> n; type *name = new type[n]; </code></pre> <p>Now, when you say <code>sizeof(name)</code>, the compiler can't know the possible future value of <code>n</code>. Therefore, it can't compute <code>sizeof(name)</code> as the real size of the array. Besides, the <code>name</code> pointer might not even point to an array!</p> <p>What should you do, you ask? Simple. Keep the size of the array in a variable and drag it around where ever you take the array. So in your case it would be like this:</p> <pre><code>void assignArray(int *myArray, int size) { for(int k = 0; k < size; ++k) { myArray[k] = k; } } </code></pre>

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