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POunderstanding variables and scope
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copied!<p>EDIT*** my question was a bit hard to understand...let me try again.</p> <p>I'm having a problem understanding variables and <em>the way they execute their value</em>.</p> <p>for example.</p> <p>if I say</p> <pre><code>$var name= 'mike'; </code></pre> <p>then if I test the page nothing will show because nothing on the HTML is requesting the value of mike.</p> <p>if I did </p> <pre><code>echo $name; </code></pre> <p>then the page would simply show mike.....</p> <p>that said, if i now do this:</p> <pre><code>$connect2db = mysqli_connect('values here'); if(!$connect2db){ die("error connecting to the database" . mysqli_error);} $db_query = mysqli_query($connect2db, "INSERT INTO email_list(email, firstname, lastname) VALUES ('$email', '$fname', '$lname')"); </code></pre> <p>for inserting these values from a form to the db, I don't understand how the connection and the commands to the db are being called and put into play because to me</p> <p>$connect2db equals to "those commands" but nothing is calling it. all $connect2db equals to literally is the instruction to take once its called into play.</p> <p>where on this chunk of code is the connection being called/put into play? where on this code block is the code being called into action(like the echo above calls $name to be put into action to display its value"???.</p> <p>I don't see anything on that connect2db variable that calls its action/connection properties to work.</p> <p>like for example if I was to say </p> <p>pseudo</p> <pre><code>if(is true){ this.$db_query; } </code></pre> <p>this I understand, this to me means that IF something evaluates to true, do the thing in the middle..</p> <p>with the original first code block, its like the variable is naming and calling itself at the same time.</p>

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