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copied!<p>Yes, you'd need to use <code>Decimal.GetBits</code>. Unfortunately, you then have to work with a 96-bit integer, and there are no simple integer type in .NET which copes with 96 bits. On the other hand, it's possible that you could use <code>Decimal</code> itself...</p> <p>Here's some code which produces the same numbers as your examples. Hope you find it useful :)</p> <pre><code>using System; public class Test { static public void Main(string[] x) { ShowInfo(123.4500m); ShowInfo(0m); ShowInfo(0.0m); ShowInfo(12.45m); ShowInfo(12.4500m); ShowInfo(770m); } static void ShowInfo(decimal dec) { // We want the integer parts as uint // C# doesn't permit int[] to uint[] conversion, // but .NET does. This is somewhat evil... uint[] bits = (uint[])(object)decimal.GetBits(dec); decimal mantissa = (bits[2] * 4294967296m * 4294967296m) + (bits[1] * 4294967296m) + bits[0]; uint scale = (bits[3] >> 16) & 31; // Precision: number of times we can divide // by 10 before we get to 0 uint precision = 0; if (dec != 0m) { for (decimal tmp = mantissa; tmp >= 1; tmp /= 10) { precision++; } } else { // Handle zero differently. It's odd. precision = scale + 1; } uint trailingZeros = 0; for (decimal tmp = mantissa; tmp % 10m == 0 && trailingZeros < scale; tmp /= 10) { trailingZeros++; } Console.WriteLine("Example: {0}", dec); Console.WriteLine("Precision: {0}", precision); Console.WriteLine("Scale: {0}", scale); Console.WriteLine("EffectivePrecision: {0}", precision - trailingZeros); Console.WriteLine("EffectiveScale: {0}", scale - trailingZeros); Console.WriteLine(); } } </code></pre>

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