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copied!<p>The FlowDocument cannot be shared by several RichTextBox controls directly..</p> <p>So you need to 'detach' that document first...</p> <p>So</p> <pre><code>RTB2.Document = RTB1.Document; </code></pre> <p>wont work and will result in your exception..</p> <pre><code>FlowDocument doc = RTB1.Document; RTB1.Document = new FlowDocument(); //Document cannot be null, so therefor the new FlowDocument instance RTB2.Document = doc; </code></pre> <p>will work like a charm...</p> <p>My code sample:</p> <p>Xaml:</p> <pre><code><Window x:Class="WpfApplication2.Window1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="Window1" Height="300" Width="300"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition /> <ColumnDefinition /> </Grid.ColumnDefinitions> <Grid.RowDefinitions> <RowDefinition /> <RowDefinition Height="Auto" /> </Grid.RowDefinitions> <RichTextBox x:Name="RTB1" /> <RichTextBox x:Name="RTB2" Grid.Column="1" /> <Button x:Name="button" Grid.Row="1" Grid.ColumnSpan="2" Content="click" Click="button_Click" /> </Grid> </Window> </code></pre> <p>Code behind..</p> <pre><code>public partial class Window1 : Window { public Window1() { InitializeComponent(); } private void button_Click(object sender, RoutedEventArgs e) { FlowDocument doc = RTB1.Document; RTB1.Document = new FlowDocument(); RTB2.Document = doc; } } </code></pre> <p>Its not the prettiest in the book, but it works...</p> <p>Hope this helps..</p>

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