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copied!<p>I wanted to post my initial attempt as the first answer but the website blocked me for around 8 hrs, and I've only been able to reply now. I've split the code into the more important snippets. </p> <p>This is my attempt so far :</p> <p>I think I should perform the following mods to the code below : </p> <pre><code> 1) Use dicts so that I have 0:000,1:001,... to improve the indexing. 2) Take the comparison string, adapt it to a list of all possible options then compare this to the full binary list e.g. 010 becomes 110,000,011 and this is then is compared to the full binary list. </code></pre> <p>My attempt to create a list of binary numbers is as follows (not using dicts yet)</p> <pre><code>def BinaryNumberList(N=4): Bins=[] for Num in range(2**N): Bin='' for Pow in sorted(range(N),reverse=True): Bin=Bin+str(Num/(2**Pow)) Num=Num-Num/(2**Pow)*2**Pow Bins.append(Bin) return Bins </code></pre> <p>Then run a for loop for comparing each string to the rest (currently not the best one)</p> <pre><code>def GreySets(Bins): for Bin1 in Bins : for Bin2 in Bins : stringXOR(Bin1,Bin2) </code></pre> <p>The string XOR I got from some one elses code on the interwebs and it returns a TrueFalseTrue (I need it to retrun the number of bits that don't match)</p> <pre><code>def stringXOR(a, b): # Error Checking msg = "Strings do not have same length: %d, %d!" assert len(a) == len(b), msg % (len(a), len(b)) cnt = len(a) - 1 # Code result = '' while cnt + 1: result = `(a[cnt] != b[cnt])` + result cnt = cnt - 1 return result </code></pre>

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