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copied!<p>First off, you should probably just learn to use <a href="http://joda-time.sourceforge.net/" rel="nofollow">Joda time</a>.</p> <p>That said, since the times are all zero padded, you can just compare strings lexically.</p> <pre><code>public static boolean inRange(String time, String range) { return time.compareTo(range.substring(0, 5)) >= 0 && time.compareTo(range.substring(6)) <= 0; } </code></pre> <p>It's good practice to fail fast on malformed inputs.</p> <pre><code>private static final Pattern VALID_TIME = Pattern.compile("[012][0-9]:[0-5][0-9]"); private static final Pattern VALID_RANGE = Pattern.compile("[012][0-9]:[0-5][0-9]-[012][0-9]:[0-5][0-9]"); </code></pre> <p>and then put an assert at the top of <code>inRange</code>:</p> <pre><code>assert VALID_TIME.matcher(time).matches() : time assert VALID_RANGE.matcher(range).matches() : range </code></pre> <p>EDIT:</p> <p>If you really need to represent the current time as a <code>Date</code>, then you should compare it this way:</p> <pre><code> public final class Range { /** Inclusive as minutes since midnight */ public final int start, end; public Range(int start, int end) { assert end >= start; } /** @param time in minutes since midnight */ public boolean contains(int time) { return start <= time && time <= end; } public static Range valueOf(String s) { assert VALID_RANGE.matcher(s).matches() : s; return new Range(minutesInDay(s.substring(0, 5)), minutesInDay(s.substring(6)); } private static int minutesInDay(String time) { return Integer.valueOf(time.substring(0, 2)) * 60 + Integer.valueOf(time.substring(3)); } } </code></pre> <p>Use <code>Range.valueOf</code> to convert from a <code>String</code>, convert your <code>Date</code> to a number of minutes since midnight in whatever timezone you like using whatever calendar implementation you like, and then use <code>Range.contains</code>.</p>

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