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copied!<p>You could try <code>.toSeq</code> for ordered collections and <code>.toSet</code> for unordered, which captures what you want as far as I understand it. </p> <p>The following passes:</p> <pre><code>class Temp extends FunSuite with ShouldMatchers { test("1") { Array(1, 2).toSeq should equal (List(1, 2).toSeq) } test("2") { Array(2, 1).toSeq should not equal (List(1, 2).toSeq) } test("2b") { Array(2, 1) should not equal (List(1, 2)) } test("3") { Iterable(2, 1).toSet should equal (Iterable(1, 2).toSet) } test("4") { Iterable(2, 1) should not equal (Iterable(1, 2)) } } </code></pre> <p>BTW a <code>Set</code> is not ordered.</p> <p><strong>edit:</strong> To avoid removing duplicate elements, try <code>toSeq.sorted</code>. The following pass:</p> <pre><code> test("5") { Iterable(2, 1).toSeq.sorted should equal (Iterable(1, 2).toSeq.sorted) } test("6") { Iterable(2, 1).toSeq should not equal (Iterable(1, 2).toSeq) } </code></pre> <p><strong>edit 2:</strong> For unordered collections where elements cannot be sorted, you can use this method:</p> <pre><code> def sameAs[A](c: Traversable[A], d: Traversable[A]): Boolean = if (c.isEmpty) d.isEmpty else { val (e, f) = d span (c.head !=) if (f.isEmpty) false else sameAs(c.tail, e ++ f.tail) } </code></pre> <p>e.g. (note use of symbols <code>'a 'b 'c</code> which have no defined ordering)</p> <pre><code> test("7") { assert( sameAs(Iterable(2, 1), Iterable(1, 2) )) } test("8") { assert( sameAs(Array('a, 'c, 'b), List('c, 'a, 'b) )) } test("9") { assert( sameAs("cba", Set('a', 'b', 'c') )) } </code></pre> <hr> <p>Alternative <code>sameAs</code> implementation: </p> <pre><code> def sameAs[A](c: Traversable[A], d: Traversable[A]) = { def counts(e: Traversable[A]) = e groupBy identity mapValues (_.size) counts(c) == counts(d) } </code></pre>

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