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POPython, loop through lines in a file; if line equals line in another file, return original line
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  1. POPython, loop through lines in a file; if line equals line in another file, return original line
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    copied!<p>Text file 1 has the following format:</p> <pre><code>'WORD': 1 'MULTIPLE WORDS': 1 'WORD': 2 </code></pre> <p>etc.</p> <p>I.e., a word separated by a colon followed by a number. </p> <p>Text file 2 has the following format:</p> <pre><code>'WORD' 'WORD' </code></pre> <p>etc. </p> <p>I need to extract single words (i.e., only WORD not MULTIPLE WORDS) from File 1 and, if they match a word in File 2, return the word from File 1 along with its value.</p> <p>I have some poorly functioning code:</p> <pre><code>def GetCounts(file1, file2): target_contents = open(file1).readlines() #file 1 as list--&gt; 'WORD': n match_me_contents = open(file2).readlines() #file 2 as list -&gt; 'WORD' ls_stripped = [x.strip('\n') for x in match_me_contents] #get rid of newlines match_me_as_regex= re.compile("|".join(ls_stripped)) for line in target_contents: first_column = line.split(':')[0] #get the first item in line.split number = line.split(':')[1] #get the number associated with the word if len(first_column.split()) == 1: #get single word, no multiple words """ Does the word from target contents match the word from match_me contents? If so, return the line from target_contents""" if re.findall(match_me_as_regex, first_column): print first_column, number #OUTPUT: WORD, n WORD, n etc. </code></pre> <p>Because of the use of regex, the output is shotty. The code will return 'asset, 2', for example, since re.findall() will match 'set' from match_me. I need to match the target_word with the entire word from match_me to block the bad output resulting from partial regex matches. </p>
 

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