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copied!<p>Whoa there.</p> <p>There's a few problems, <strike>but your segfault is probably because you're passing a <code>char*</code> -- which is just a pointer, and then trying to <code>cout</code> it in <code>disp()</code>. Problem is, that pointer does not live in <code>disp()</code>, it lives in <code>main()</code>. You probably want to either deep-copy the <code>char*</code>, or use <code>std::string</code>. Doing it this way will not work.</strike></p> <p><strong>EDIT</strong>: </p> <p><em>See EDIT 2</em></p> <p>You can not just assign name to the class's <code>name</code> variable. If you do that, you'll get unpredictable results - and you'll probably STILL segfault. Remember: in C/C++, objects are locally scoped unless allocated on the heap. In this case, in your ctor, you'd want to do something like:</p> <pre><code>this->name = new char[ strlen( name ) + 1 ]; strcpy( this->name, name ); </code></pre> <p>And in the destructor, you'll want to do something like:</p> <pre><code>delete [] this->name; </code></pre> <p>Note: my syntax may be completely wrong, and I realize the above code is inherently unsafe as you're not checking the <code>char*</code> to make sure it's not NULL, and you're not checking the return value of <code>new.</code> Nevertheless, this should get you started.</p> <p><strong>EDIT 2:</strong> I stand corrected. String literals are treated as constant storage and thus live on for the duration of the program. <em>Nevertheless</em>, the lesson, I believe, is important: <strong>in general, when not dealing with string literals</strong>, passing a pointer (or array, etc.), you need to allocate storage for it and deep-copy. You also need to de-allocate appropriately when destroying said object.</p>

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