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copied!<p>I think deriving your class from a base class is not relevant to the question here, that's a mere implementation detail. What you really seem to be after is if there's a way to partially specialize member functions, like the constructor. Do you want something like this?</p> <pre><code>template <typename T, int N> class Foo { Foo(); // general template <typename U> Foo<U, 2>(); // specialized, NOT REAL CODE }; </code></pre> <p>This doesn't work. You always have to specialize the entire class. The reason is simple: You have to know the full type of the class first <em>before</em> you even know which member functions exist. Consider the following simple situation:</p> <pre><code>template <typename T> class Bar { void somefunction(const T&); }; template <> class Bar<int> { double baz(char, int); }; </code></pre> <p>Now <code>Bar<T>::somefunction()</code> depends on <code>T</code>, but the function only <em>exists</em> when <code>T</code> is not <code>int</code>, because <code>Bar<int></code> is an entirely different class.</p> <p>Or consider even another specialization <code>template <> class Bar<double> : public Zip {};</code> -- even the polymorphic nature of a class can be entirely different in a specialization!</p> <p>So the only way you can provide <s>specializations</s> new declarations of members, including constructors, is by specializing the entire class. (You <em>can</em> specialize the <em>definition</em> of existing functions, see @Alf's answer.)</p>

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