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POBASH: Sort array of files with crazy names
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  1. POBASH: Sort array of files with crazy names
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    copied!<p>Problem:</p> <p>Need to sort array before operating on them with function.</p> <p>First, array is loaded with files:</p> <pre><code>unset a i counter=1 while IFS= read -r -d $'\0' file; do a[i++]="$file" done &lt; &lt;(find $DIR -type f -print0) </code></pre> <p>Next, each member of array is sent to function</p> <pre><code>for f in "${a[@]}" do func_hash "$f" [ $(expr $counter % 20) -eq 0 ] &amp;&amp; printf "=" counter=$((counter + 1)) done </code></pre> <p>Somehow a sort needs to be thrown into the above for loop. Have looked through the SO posts on sorting arrays but somehow my crazy file names cause issues when I try to tack on a sort.</p> <p>Ideas?</p> <p>Thanks!</p> <p>Bubnoff</p> <p><strong>UPDATE:</strong> Here's code with sort:</p> <pre><code>while IFS= read -r -d $'\0' file; do func_hash "$file" [ $(expr $counter % 20) -eq 0 ] &amp;&amp; printf "=" counter=$((counter + 1)) done &lt; &lt;(find $DIR -type f -print0 | sort -z +1 -1) </code></pre> <p>It's sorting by full path rather than file name. Any ideas on how to sort by file name given that the path is needed for the function?</p> <p><strong>UPDATE 2:</strong> Decided to compromise.</p> <p>My main goal was to avoid temp files using sort. GNU sort can write back to the original file with its '-o' option so now I can:</p> <pre><code>sort -o $OUT -t',' -k 1 $OUT </code></pre> <p>Anyone have a more 'elegant' solution ( whatever that means ).</p> <p><strong>SOLVED</strong> See jw013's answer below. Thanks man!</p>
 

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