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PORequest parameters in Spring MVC
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copied!<p>How to pass it, when I got these configuration:</p> <pre><code> <servlet> <servlet-name>spring</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.htm</url-pattern> </servlet-mapping> </code></pre> <p>In my controller:</p> <pre><code>@RequestMapping(value="/list.htm", method=RequestMethod.GET) public ModelAndView list(HttpServletRequest request, HttpServletResponse response, @RequestParam(value="start", required=false) String start, @RequestParam(value="end", required=false) String end)throws Exception{ ModelMap modelMap = new ModelMap(); modelMap.addAttribute("list", cpvCodeDAO.list(Integer.parseInt(start),Integer.parseInt(end))); return new ModelAndView("list", modelMap); } </code></pre> <p>When i put: "http:... /list.htm?start=0&end=100" I got error stacktrace like this:</p> <blockquote> <p>org.springframework.web.util.NestedServletException: Request processing failed; nested exception is java.lang.IllegalArgumentException: wrong number of arguments org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:625) org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:525) javax.servlet.http.HttpServlet.service(HttpServlet.java:621) javax.servlet.http.HttpServlet.service(HttpServlet.java:722)</p> </blockquote>

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