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POhow to be sure that two directories are not subdirectories to each other (BASH)
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copied!<p><strong>EDITED:</strong> this is more or less what I came up after @Mechanical's nice input. Any insight?</p> <pre><code>#!/bin/bash path1="$(readlink -e "$1")" path2="$(readlink -e "$2")" EBADARGS=65 function checkArgsNumber() { if test "$#" -ne 2; then echo "ERRORE: this script takes exactly 2 params." exit $EBADARGS fi } function checkExistence() { if [ ! -d $path1 ]; then echo "ERROR: "$1" does not exist" exit $EBADARGS elif [ ! -d "$2" ]; then echo "ERROR: "$2" does not exist" exit $EBADARGS elif [[ -L $path1 ]]; then echo "ERROR: path1 can't be a symbolic link" exit $EBADARGS elif [[ -L $2 ]]; then echo "ERROR: path2 can't be a symbolic link" exit $EBADARGS fi } function checkIfSame() { if [[ $path1 == $path2 ]]; then echo "ERROR: path1 and path2 must be different directories" exit $EBADARGS fi } function checkIfSubdirectories() { if [[ $path1 = *$path2* ]]; then echo "ERROR:"$1" is a $path2 subdirectory" exit $EBADARGS elif [[ $path2 = *$path1* ]]; then echo "ERROR:"$2" is a $path1 subdirectory" exit $EBADARGS elif [[ -e "$(find $path1 -samefile $path2)" ]]; then echo "ERROR:"$(find $path1 -samefile $path2 -print0)" and "$2" have the same inode, $path2 is a $path1 subdirectory" exit $EBADARGS elif [[ -e "$(find $path2 -samefile $path1)" ]]; then echo "ERROR:"$(find $path2 -samefile $path1 -print0)" and "$2" have the same inode, $path1 is a $path2 subdirectory" exit $EBADARGS fi } checkArgsNumber "$@" checkExistence "$@" checkIfSame "$@" checkIfSubdirectories "$@" </code></pre> <p>now.. this should work and I hope it is useful somehow. Could someone explain me how the <code>*$path2*</code> part works? What is the name of this <code>* *</code> operator? Where should I go read about it? </p>

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