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POlogging blocks of code to log files in bash
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  1. POlogging blocks of code to log files in bash
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    copied!<p>I have a huge bash script and I want to log specific blocks of code to a specific &amp; small log files (instead of just one huge log file).</p> <p>I have the following two methods: </p> <pre><code># in this case, 'log' is a bash function # Using code block &amp; piping { # ... bash code ... } | log "file name" # Using Process Substitution log "file name" &lt; &lt;( # ... bash code ... ) </code></pre> <p>Both methods may interfere with the proper execution of the bash script, e.g. when assigning values to a variable (like the problem presented <a href="https://stackoverflow.com/questions/6255303/bash-piping-prevents-global-variable-assignment">here</a>).<br> How do you suggest to log the output of commands to log files? </p> <hr> <p><strong>Edit:</strong> This is what I tried to do (besides many other variations), but doesn't work as expected:</p> <pre><code>function log() { if [ -z "$counter" ]; then counter=1 echo "" &gt;&gt; "./General_Log_File" # Create the summary log file else (( ++counter )) fi echo "" &gt; "./${counter}_log_file" # Create specific log file # Display text-to-be-logged on screen &amp; add it to the summary log file # &amp; write text-to-be-logged to it's corresponding log file exec 1&gt; &gt;(tee "./${counter}_log_file" | tee -a "./General_Log_File") 2&gt;&amp;1 } log # Logs the following code block { # ... Many bash commands ... } log # Logs the following code block { # ... Many bash commands ... } </code></pre> <p>The results of executions varies: sometimes the log files are created and sometimes they don't (which raise an error).</p>
 

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