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copied!<p>I had this problem so I have tested the example below. The solution relies on calling "startActivity" from the MapActivity context. </p> <p>If your map is actually working with overlays then you have already passed the MapView Context to your custom ItemizedOverlay constructor and you probably assigned the MapView Context to a class variable called mContext (I'm making assumptions that you followed Google's MapView example). So in your custom Overlay's onTap function, do this: </p> <pre><code> @Override protected boolean onTap(int index) { Intent intent = new Intent(mContext, ActivityYouAreTryingToLaunch.class); mContext.startActivity(intent); return true; } </code></pre> <p>But you probably want to pass something to the new Activity you are trying to launch so your new activity can do something useful with your selection. So...</p> <pre><code> @Override protected boolean onTap(int index) { OverlayItem item = mOverlays.get(index); //assumption: you decided to store an "id" in the snippet so you can associate this map location with your new Activity long id = Long.parseLong(item.getSnippet()); //Snippet is a built-in String property of an Overlay object. //pass an "id" to the class so you can query Intent intent = new Intent(mContext, ActivityYouAreTryingToLaunch.class); String action = Intent.ACTION_PICK; //You can substitute with any action that is relevant to the class you are calling //I create a URI this way because I append the id to the end of the URI (lookup the NotePad example for help because there are many ways to build a URI) Uri uri = ContentUris.withAppendedId(Your_CONTENT_URI, id); //set the action and data for this Intent intent.setAction(action); intent.setData(uri); //call the class mContext.startActivity(intent); return true; } </code></pre>

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