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POstrongly-typed partial views MVC RC1
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  1. POstrongly-typed partial views MVC RC1
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    copied!<p>having a problem passing ViewData.Model to the partial views. It always is defaulting to null even if I equate it to a result query. I cannot access the strongly typed data because the Model is null. My current code is this, </p> <p>ViewPage</p> <pre><code>&lt;asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"&gt; &lt;% Html.RenderPartial("header", this.ViewData.Model); %&gt; &lt;% Html.RenderPartial("test", this.ViewData.Model); %&gt; &lt;div id="userControls"&gt; &lt;/div&gt; &lt;/asp:Content&gt; </code></pre> <p>UserControl - header</p> <pre><code>&lt;%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl&lt;testMVCProject.Models.information&gt;" %&gt; &lt;h2&gt; ACReport&lt;/h2&gt; &lt;p&gt; id: &lt;%= Html.Encode(Model.id) %&gt; &lt;/p&gt; &lt;p&gt; type: &lt;%= Html.Encode(Model.type) %&gt; &lt;/p&gt; </code></pre> <p>UserControl - test</p> <pre><code>&lt;%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl&lt;testMVCProject.Models.information&gt;" %&gt; &lt;% using (Ajax.BeginForm( "pressureV2", "Home", new { id = ViewData.Model.id }, new AjaxOptions { UpdateTargetId = "userControls", HttpMethod = "GET" }, new { @id = "genInfoLinkForm" })) {%&gt; &lt;%= Html.SubmitButton("hey", "Lol") %&gt; &lt;%} %&gt; </code></pre> <p>Controller</p> <pre><code>public ActionResult header(int id) { var headerResults = from c in db.information where c.id == id select new information { id = c.id, type = c.type }; ViewData.Model = headerResults.FirstOrDefault(); return View(ViewData.Model); } public ActionResult pressureV2(int id) { var pressureVResults = from c in db.pressure_volume_tests where c.id == id select new pressureVT { bottomCVP = c.bottom_CVP, topCVP = c.top_CVP }; ViewData.Model = pressureVResults.FirstOrDefault(); return View(ViewData.Model); } </code></pre>
 

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