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POHow to update a model but return unmodified model in Django?
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copied!<p>I'm using <a href="https://bitbucket.org/jespern/django-piston/wiki/Home" rel="nofollow">django-piston</a> to write a RESTful Web Service and have a problem.</p> <p>in models.py:</p> <pre><code>class Status(models.Model): user = models.ForeignKey(User) content = models.TextField(max_length=140) class StatusReply(models.Model): user = models.ForeignKey(User) reply_to = models.ForeignKey(Status, related_name='replies') content = models.TextField(max_length=140) has_read = models.BooleanField(default=False, help_text="has the publisher of the status read the reply") </code></pre> <p>in handlers.py:</p> <pre><code>class StatusHandler(BaseHandler): allowed_methods = ('GET', 'POST', 'DELETE' ) model = Status fields = ('id', ('user', ('id', 'username', 'name')), 'content', ('replies', ('id', ('user', ('id', 'username', 'name')), 'content', 'has_read'), ), ) @need_login def read(self, request, id, current_user): # the current_user arg is an instance of user created in @need_login try: status = Status.objects.get(pk=id) except ObjectDoesNotExist: return rc.NOT_FOUND else: if status.user == current_user: #if current_user is the publisher of the status, set all replies read status.replies.all().update(has_read=True) return status </code></pre> <p>In the handler, it returned a specific status by id. Now I want to return the status before <code>status.replies.all().update(has_read=True)</code> but also do the update operation in database. How to do it? Thanks in advance.</p>

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